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added 2 commits
June 7, 2019 15:51
jianyuewu
reviewed
Jun 7, 2019
| if (!l1 && !l2) { | ||
| return null; | ||
| } | ||
| let head = new ListNode(null); |
jianyuewu
reviewed
Jun 7, 2019
| */ | ||
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| // 递归法 | ||
| var treeSymmetric = function(t1, t2) { |
Contributor
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t1, t2，最好能写成left, right, 容易懂些。
jianyuewu
reviewed
Jun 7, 2019
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| // 递归法 | ||
| var treeSymmetric = function(t1, t2) { | ||
| if (t1 == null && t2 == null) { |
Contributor
There was a problem hiding this comment.
不懂javascript，不过可能四行可以合并为两行：
if (t1 == null || t2 == null) {
return t1 == t2;
}
Contributor
请按照代码文件命名规则进行命名：LeetCode_题目序号_学号，比如学号为 0 的学员完成 LeetCode_33_108 的第 2 题 后，请将代码文件名保存为 LeetCode_2_0.py (假设你使用的是 Python 语言)。 |
Author
我的哪里不符合规则，我没看出来命名有什么问题？？ |
GeekUniversity
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Jun 24, 2019
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还差4道题未提交；
174（递归解法报超时，dp不太理解）、42（和84一样只会暴力解法）、783、938（这两个有部分case没过去，需要看）